Выполните деление:
\(\displaystyle 3\) | \(\displaystyle 0\) | \(\displaystyle 1\) | \(\displaystyle 5\) | \(\displaystyle 7\) | \(\displaystyle 5\) | \(\displaystyle 6\) | \(\displaystyle 9\) | |
\(\displaystyle –\) | ||||||||
\(\displaystyle –\) | ||||||||
\(\displaystyle 0\) |
1. Выбираем первые три цифры и делим число \(\displaystyle 301\) на \(\displaystyle 569\) с остатком, но \(\displaystyle 301<569\) поэтому мы сносим следующий разряд числа \(\displaystyle 301{\bf5}7\) (это цифра \(\displaystyle 5\)).
Делим число \(\displaystyle 3015\) на \(\displaystyle 569\) с остатком:
\(\displaystyle 3015=2845+170=569\cdot {\bf 5}+ 170{\small.}\)
Пишем \(\displaystyle \bf 5\) первой цифрой в частном и число \(\displaystyle 2845\) под числом \(\displaystyle 3015{\small:}\)
\(\displaystyle 3\) | \(\displaystyle 0\) | \(\displaystyle 1\) | \(\displaystyle 5\) | \(\displaystyle 7\) | \(\displaystyle 5\) | \(\displaystyle 6\) | \(\displaystyle 9\) | |
\(\displaystyle –\) | ||||||||
\(\displaystyle \bf 2\) | \(\displaystyle \bf 8\) | \(\displaystyle \bf 4\) | \(\displaystyle \bf 5\) | \(\displaystyle \bf 5\) | \(\displaystyle {\small?}\) | |||
\(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
\(\displaystyle –\) | ||||||||
\(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
\(\displaystyle 0\) |
2. Вычитаем \(\displaystyle 3015-2845={\bf 170}{\small:}\)
\(\displaystyle 3\) | \(\displaystyle 0\) | \(\displaystyle 1\) | \(\displaystyle 5\) | \(\displaystyle 7\) | \(\displaystyle 5\) | \(\displaystyle 6\) | \(\displaystyle 9\) | |
\(\displaystyle –\) | ||||||||
\(\displaystyle 2\) | \(\displaystyle 8\) | \(\displaystyle 4\) | \(\displaystyle 5\) | \(\displaystyle 5\) | \(\displaystyle {\small?}\) | |||
\(\displaystyle \bf 1\) | \(\displaystyle \bf 7\) | \(\displaystyle \bf 0\) | \(\displaystyle {\small?}\) | |||||
\(\displaystyle –\) | ||||||||
\(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
\(\displaystyle 0\) |
3. Сносим единицы числа \(\displaystyle 3015{\bf 7}\) (это цифра \(\displaystyle 7 \)):
\(\displaystyle 3\) | \(\displaystyle 0\) | \(\displaystyle 1\) | \(\displaystyle 5\) | \(\displaystyle \bf 7\) | \(\displaystyle 5\) | \(\displaystyle 6\) | \(\displaystyle 9\) | |
\(\displaystyle –\) | ||||||||
\(\displaystyle 2\) | \(\displaystyle 8\) | \(\displaystyle 4\) | \(\displaystyle 5\) | \(\displaystyle 5\) | \(\displaystyle {\small?}\) | |||
\(\displaystyle 1\) | \(\displaystyle 7\) | \(\displaystyle 0\) | \(\displaystyle \bf 7\) | |||||
\(\displaystyle –\) | ||||||||
\(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | \(\displaystyle {\small?}\) | |||||
\(\displaystyle 0\) |
4. Делим число \(\displaystyle 1707\) на \(\displaystyle 569{\small:}\)
\(\displaystyle 1707=569 \cdot {\bf 3}{\small.}\)
Пишем \(\displaystyle \bf 3\) второй цифрой в частном и \(\displaystyle 1707\) под \(\displaystyle 1707{\small:}\)
\(\displaystyle 3\) | \(\displaystyle 0\) | \(\displaystyle 1\) | \(\displaystyle 5\) | \(\displaystyle 7\) | \(\displaystyle 5\) | \(\displaystyle 6\) | \(\displaystyle 9\) | |
\(\displaystyle –\) | ||||||||
\(\displaystyle 2\) | \(\displaystyle 8\) | \(\displaystyle 4\) | \(\displaystyle 5\) | \(\displaystyle 5\) | \(\displaystyle \bf 3\) | |||
\(\displaystyle 1\) | \(\displaystyle 7\) | \(\displaystyle 0\) | \(\displaystyle 7\) | |||||
\(\displaystyle –\) | ||||||||
\(\displaystyle 1\) | \(\displaystyle 7\) | \(\displaystyle 0\) | \(\displaystyle 7\) | |||||
\(\displaystyle 0\) |