Поверните устройство

Поверните устройство

Skip to main content

Теория: Построение графика функции\(\displaystyle y=x^{2}\)(короткая версия)

Задание

Заполните таблицу значений квадратичной функции \(\displaystyle y=x^2{\small :}\)
 

\(\displaystyle x\)\(\displaystyle -1\)\(\displaystyle -0{,}8\)\(\displaystyle -0{,}6\)\(\displaystyle -0{,}4\)\(\displaystyle -0{,}3\)\(\displaystyle 0\)\(\displaystyle 0{,}3\)\(\displaystyle 0{,}4\)\(\displaystyle 0{,}6\)\(\displaystyle 0{,}8\)\(\displaystyle 1\)
\(\displaystyle y=x^2\)


Мысленно постройте график квадратичной функции \(\displaystyle y=x^2\) по полученным точкам:
 

Решение

Заполним таблицу значений квадратичной функции \(\displaystyle y=x^2{\small :}\)

\(\displaystyle x\)\(\displaystyle -1\)\(\displaystyle -0{,}8\)\(\displaystyle -0{,}6\)\(\displaystyle -0{,}4\)\(\displaystyle -0{,}3\)\(\displaystyle 0\)\(\displaystyle 0{,}3\)\(\displaystyle 0{,}4\)\(\displaystyle 0{,}6\)\(\displaystyle 0{,}8\)\(\displaystyle 1\)
\(\displaystyle y=x^2\)\(\displaystyle (-1)^2\)\(\displaystyle (-0{,}8)^2\)\(\displaystyle (-0{,}6)^2\)\(\displaystyle (-0{,}4)^2\)\(\displaystyle (-0{,}3)^2\)\(\displaystyle 0\)\(\displaystyle 0{,}3^2\)\(\displaystyle 0{,}4^2\)\(\displaystyle 0{,}6^2\)\(\displaystyle 0{,}8^2\)\(\displaystyle 1^2\)


Вычислим значения:

\(\displaystyle x\)\(\displaystyle -1\)\(\displaystyle -0{,}8\)\(\displaystyle -0{,}6\)\(\displaystyle -0{,}4\)\(\displaystyle -0{,}3\)\(\displaystyle 0\)\(\displaystyle 0{,}3\)\(\displaystyle 0{,}4\)\(\displaystyle 0{,}6\)\(\displaystyle 0{,}8\)\(\displaystyle 1\)
\(\displaystyle y=x^2\)\(\displaystyle 1\)\(\displaystyle 0{,}64\)\(\displaystyle 0{,}36\)\(\displaystyle 0{,}16\)\(\displaystyle 0{,}09\)\(\displaystyle 0\)\(\displaystyle 0{,}09\)\(\displaystyle 0{,}16\)\(\displaystyle 0{,}36\)\(\displaystyle 0{,}64\)\(\displaystyle 1\)


Построим точки на плоскости:


Соединим полученные точки:


Получили график функции \(\displaystyle y=x^2\) на отрезке \(\displaystyle [-1{\small ;}1]{\small .} \)


Замечание / комментарий

Построение по точкам

Чем больше возьмём точек с абсциссами от \(\displaystyle -1 \) до \(\displaystyle 1{\small , } \) тем точнее  сможем изобразить график функции \(\displaystyle y=x^2\) на отрезке \(\displaystyle [-1{\small ;}1]{\small : } \)