1. Делим \(\displaystyle 6\) на \(\displaystyle 6\) с остатком.
Найдем, какое максимальное количество \(\displaystyle \color{blue}{6}\) можно забрать из \(\displaystyle 6{\small .}\)
То есть найдем неполное частное при делении \(\displaystyle 6\) на \(\displaystyle \color{blue}{6}\) с остатком.
Так как
\(\displaystyle 6=\color{green}{1} \cdot \color{blue}{6}+0{\small ,}\)
то можно забрать \(\displaystyle \color{green}{1}\) (одну) шестерку.
Поэтому пишем \(\displaystyle \color{green}{1}\) в частное:
| \(\displaystyle -\) | \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 8\) | \(\displaystyle \small 6\) | | |
| \(\displaystyle \small ?\) | | | \(\displaystyle \small \color{green}{1}\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) |
| \(\displaystyle -\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | | | |
| | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | | | |
| | | | \(\displaystyle \small 0\) | | | |
2. Далее, вычитаем в столбик из \(\displaystyle 6\) произведение \(\displaystyle \color{blue}{6}\cdot \color{green}{1}=\color{green}{6}{\small : }\)
| \(\displaystyle -\) | \(\displaystyle \small \color{orange}{6}\) | \(\displaystyle \small 1\) | \(\displaystyle \small 8\) | \(\displaystyle \small 6\) | | |
| \(\displaystyle \small \color{green}{ 6}\) | | | \(\displaystyle \small 1\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) |
| \(\displaystyle -\) | \(\displaystyle \small 0\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | | | |
| | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | | | |
| | | | \(\displaystyle \small 0\) | | | |
3. Сносим цифру из разряда десятков \(\displaystyle 6{\underline 1}8{\small : }\)
| \(\displaystyle -\) | \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 8\) | \(\displaystyle \small 6\) | | |
| \(\displaystyle \small 6\) | | | \(\displaystyle \small 1\) | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) |
| \(\displaystyle -\) | \(\displaystyle \small 0\) | \(\displaystyle \small \color{red}{ 1}\) | \(\displaystyle \small ?\) | | | |
| | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | | | |
| | | | \(\displaystyle \small 0\) | | | |
4. Так как \(\displaystyle \color{red}{ 1}\) меньше, чем \(\displaystyle 6{\small ,}\) то сносим следующую цифру (единицы числа \(\displaystyle 61{\underline8}{\small ,}\) то есть цифру \(\displaystyle 8\)), а в частном записываем нуль:
| \(\displaystyle -\) | \(\displaystyle \small 6\) | \(\displaystyle \small 1\) | \(\displaystyle \small 8\) | \(\displaystyle \small 6\) | | |
| \(\displaystyle \small 6\) | | | \(\displaystyle \small 1\) | \(\displaystyle \small \color{green}{ 0}\) | \(\displaystyle \small ?\) |
| \(\displaystyle -\) | \(\displaystyle \small 0\) | \(\displaystyle \small \color{red}{ 1}\) | \(\displaystyle \small \color{red}{ 8}\) | | | |
| | \(\displaystyle \small ?\) | \(\displaystyle \small ?\) | | | |
| | | | \(\displaystyle \small 0\) | | | |
Получили число \(\displaystyle 18{\small .}\)
